Base | Representation |
---|---|
bin | 110011011001… |
… | …000110000011 |
3 | 221100110021211 |
4 | 303121012003 |
5 | 11422102011 |
6 | 1200430551 |
7 | 222340231 |
oct | 63310603 |
9 | 27313254 |
10 | 13472131 |
11 | 76718a2 |
12 | 4618457 |
13 | 2a3909a |
14 | 1b09951 |
15 | 12b1b21 |
hex | cd9183 |
13472131 has 4 divisors (see below), whose sum is σ = 13482064. Its totient is φ = 13462200.
The previous prime is 13472093. The next prime is 13472161. The reversal of 13472131 is 13127431.
13472131 is nontrivially palindromic in base 15.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 13472131 - 27 = 13472003 is a prime.
It is a super-2 number, since 2×134721312 = 362996627362322, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13472161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2535 + ... + 5776.
It is an arithmetic number, because the mean of its divisors is an integer number (3370516).
Almost surely, 213472131 is an apocalyptic number.
13472131 is a deficient number, since it is larger than the sum of its proper divisors (9933).
13472131 is an equidigital number, since it uses as much as digits as its factorization.
13472131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9932.
The product of its digits is 504, while the sum is 22.
The square root of 13472131 is about 3670.4401643400. The cubic root of 13472131 is about 237.9461957324.
Adding to 13472131 its reverse (13127431), we get a palindrome (26599562).
The spelling of 13472131 in words is "thirteen million, four hundred seventy-two thousand, one hundred thirty-one".
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