Base | Representation |
---|---|
bin | 111110101111001000… |
… | …1101110011001101011 |
3 | 110212202021011012221221 |
4 | 1331132101232121223 |
5 | 4201404234102422 |
6 | 141520411042511 |
7 | 12506425323046 |
oct | 1753621563153 |
9 | 425667135857 |
10 | 134725690987 |
11 | 5215615a778 |
12 | 2213b440437 |
13 | c920c5c1a4 |
14 | 6740d63c5d |
15 | 3787b833c7 |
hex | 1f5e46e66b |
134725690987 has 2 divisors, whose sum is σ = 134725690988. Its totient is φ = 134725690986.
The previous prime is 134725690973. The next prime is 134725691021. The reversal of 134725690987 is 789096527431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134725690987 - 231 = 132578207339 is a prime.
It is a super-2 number, since 2×1347256909872 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134725690937) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67362845493 + 67362845494.
It is an arithmetic number, because the mean of its divisors is an integer number (67362845494).
It is a 1-persistent number, because it is pandigital, but 2⋅134725690987 = 269451381974 is not.
Almost surely, 2134725690987 is an apocalyptic number.
134725690987 is a deficient number, since it is larger than the sum of its proper divisors (1).
134725690987 is an equidigital number, since it uses as much as digits as its factorization.
134725690987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22861440, while the sum is 61.
The spelling of 134725690987 in words is "one hundred thirty-four billion, seven hundred twenty-five million, six hundred ninety thousand, nine hundred eighty-seven".
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