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13480901347 is a prime number
BaseRepresentation
bin11001000111000011…
…00011101011100011
31021210111200202002111
430203201203223203
5210102102320342
610105410300151
7655032525244
oct144341435343
937714622074
1013480901347
115798687791
122742887657
13136abcaa04
1491c58cccb
1553d796217
hex323863ae3

13480901347 has 2 divisors, whose sum is σ = 13480901348. Its totient is φ = 13480901346.

The previous prime is 13480901341. The next prime is 13480901389. The reversal of 13480901347 is 74310908431.

13480901347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (74310908431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13480901347 - 215 = 13480868579 is a prime.

It is a super-2 number, since 2×134809013472 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13480901341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6740450673 + 6740450674.

It is an arithmetic number, because the mean of its divisors is an integer number (6740450674).

Almost surely, 213480901347 is an apocalyptic number.

13480901347 is a deficient number, since it is larger than the sum of its proper divisors (1).

13480901347 is an equidigital number, since it uses as much as digits as its factorization.

13480901347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 40.

The spelling of 13480901347 in words is "thirteen billion, four hundred eighty million, nine hundred one thousand, three hundred forty-seven".