Base | Representation |
---|---|
bin | 11001000111000111… |
… | …10001010011110010 |
3 | 1021210112210012212002 |
4 | 30203203301103302 |
5 | 210102224401313 |
6 | 10105430534002 |
7 | 655040462444 |
oct | 144343612362 |
9 | 37715705762 |
10 | 13481481458 |
11 | 5798a43615 |
12 | 2742b07302 |
13 | 136b071a83 |
14 | 91c6a0494 |
15 | 53d85d058 |
hex | 3238f14f2 |
13481481458 has 4 divisors (see below), whose sum is σ = 20222222190. Its totient is φ = 6740740728.
The previous prime is 13481481449. The next prime is 13481481479. The reversal of 13481481458 is 85418418431.
13481481458 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 85418418431 = 5237 ⋅16310563.
It can be written as a sum of positive squares in only one way, i.e., 10469996329 + 3011485129 = 102323^2 + 54877^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3370370363 + ... + 3370370366.
Almost surely, 213481481458 is an apocalyptic number.
13481481458 is a deficient number, since it is larger than the sum of its proper divisors (6740740732).
13481481458 is an equidigital number, since it uses as much as digits as its factorization.
13481481458 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6740740731.
The product of its digits is 491520, while the sum is 47.
Adding to 13481481458 its reverse (85418418431), we get a palindrome (98899899889).
The spelling of 13481481458 in words is "thirteen billion, four hundred eighty-one million, four hundred eighty-one thousand, four hundred fifty-eight".
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