Base | Representation |
---|---|
bin | 11001000111010101… |
… | …00000001100110111 |
3 | 1021210200002212212222 |
4 | 30203222200030313 |
5 | 210103202341031 |
6 | 10105532432555 |
7 | 655061463146 |
oct | 144352401467 |
9 | 37720085788 |
10 | 13483246391 |
11 | 5799a3963a |
12 | 274361875b |
13 | 136b53c204 |
14 | 91c9dd75d |
15 | 53daaae7b |
hex | 323aa0337 |
13483246391 has 4 divisors (see below), whose sum is σ = 13483795512. Its totient is φ = 13482697272.
The previous prime is 13483246379. The next prime is 13483246411. The reversal of 13483246391 is 19364238431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 19364238431 = 47 ⋅412005073.
It is a cyclic number.
It is not a de Polignac number, because 13483246391 - 26 = 13483246327 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13483246351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235916 + ... + 287441.
It is an arithmetic number, because the mean of its divisors is an integer number (3370948878).
Almost surely, 213483246391 is an apocalyptic number.
13483246391 is a deficient number, since it is larger than the sum of its proper divisors (549121).
13483246391 is an equidigital number, since it uses as much as digits as its factorization.
13483246391 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 549120.
The product of its digits is 373248, while the sum is 44.
The spelling of 13483246391 in words is "thirteen billion, four hundred eighty-three million, two hundred forty-six thousand, three hundred ninety-one".
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