Base | Representation |
---|---|
bin | 11001000111011110… |
… | …00010010111000011 |
3 | 1021210202100021012012 |
4 | 30203233002113003 |
5 | 210104003404013 |
6 | 10110014123135 |
7 | 655104543143 |
oct | 144357022703 |
9 | 37722307165 |
10 | 13484434883 |
11 | 579a680567 |
12 | 2743ab04ab |
13 | 136b86716a |
14 | 91cc2c923 |
15 | 53dc431a8 |
hex | 323bc25c3 |
13484434883 has 2 divisors, whose sum is σ = 13484434884. Its totient is φ = 13484434882.
The previous prime is 13484434823. The next prime is 13484434891. The reversal of 13484434883 is 38843448431.
13484434883 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13484434883 - 218 = 13484172739 is a prime.
It is a super-2 number, since 2×134844348832 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13484434823) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6742217441 + 6742217442.
It is an arithmetic number, because the mean of its divisors is an integer number (6742217442).
Almost surely, 213484434883 is an apocalyptic number.
13484434883 is a deficient number, since it is larger than the sum of its proper divisors (1).
13484434883 is an equidigital number, since it uses as much as digits as its factorization.
13484434883 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3538944, while the sum is 50.
The spelling of 13484434883 in words is "thirteen billion, four hundred eighty-four million, four hundred thirty-four thousand, eight hundred eighty-three".
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