Base | Representation |
---|---|
bin | 11001000111100001… |
… | …11101110011001101 |
3 | 1021210210021221202111 |
4 | 30203300331303031 |
5 | 210104121043433 |
6 | 10110033024021 |
7 | 655112050213 |
oct | 144360756315 |
9 | 37723257674 |
10 | 13484940493 |
11 | 579a996422 |
12 | 27440b5011 |
13 | 136b9b333b |
14 | 91cd20cb3 |
15 | 53dce2dcd |
hex | 323c3dccd |
13484940493 has 2 divisors, whose sum is σ = 13484940494. Its totient is φ = 13484940492.
The previous prime is 13484940451. The next prime is 13484940499. The reversal of 13484940493 is 39404948431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9032981764 + 4451958729 = 95042^2 + 66723^2 .
It is a cyclic number.
It is not a de Polignac number, because 13484940493 - 217 = 13484809421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13484940499) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6742470246 + 6742470247.
It is an arithmetic number, because the mean of its divisors is an integer number (6742470247).
Almost surely, 213484940493 is an apocalyptic number.
It is an amenable number.
13484940493 is a deficient number, since it is larger than the sum of its proper divisors (1).
13484940493 is an equidigital number, since it uses as much as digits as its factorization.
13484940493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1492992, while the sum is 49.
The spelling of 13484940493 in words is "thirteen billion, four hundred eighty-four million, nine hundred forty thousand, four hundred ninety-three".
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