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13485470241617 = 111225951840147
BaseRepresentation
bin1100010000111101010010…
…1010011101001101010001
31202202012100121102001001122
43010033110222131031101
53231421220340212432
644403050044412025
72561202344514323
oct304172452351521
952665317361048
1013485470241617
11432a179427710
1216196a8847015
1376a89c82320a
143489b3671613
15185bc48e1612
hexc43d4a9d351

13485470241617 has 4 divisors (see below), whose sum is σ = 14711422081776. Its totient is φ = 12259518401460.

The previous prime is 13485470241601. The next prime is 13485470241623. The reversal of 13485470241617 is 71614207458431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13485470241617 - 24 = 13485470241601 is a prime.

It is a super-3 number, since 3×134854702416173 (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13485470241517) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 612975920063 + ... + 612975920084.

It is an arithmetic number, because the mean of its divisors is an integer number (3677855520444).

Almost surely, 213485470241617 is an apocalyptic number.

It is an amenable number.

13485470241617 is a deficient number, since it is larger than the sum of its proper divisors (1225951840159).

13485470241617 is a wasteful number, since it uses less digits than its factorization.

13485470241617 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1225951840158.

The product of its (nonzero) digits is 4515840, while the sum is 53.

The spelling of 13485470241617 in words is "thirteen trillion, four hundred eighty-five billion, four hundred seventy million, two hundred forty-one thousand, six hundred seventeen".

Divisors: 1 11 1225951840147 13485470241617