Base | Representation |
---|---|
bin | 11001000111110001… |
… | …10100111100010001 |
3 | 1021210221011122201221 |
4 | 30203320310330101 |
5 | 210110133020421 |
6 | 10110145125041 |
7 | 655135422451 |
oct | 144370647421 |
9 | 37727148657 |
10 | 13487001361 |
11 | 57a1073819 |
12 | 2744929781 |
13 | 136c2553a2 |
14 | 91d2d9d61 |
15 | 53e09d841 |
hex | 323e34f11 |
13487001361 has 2 divisors, whose sum is σ = 13487001362. Its totient is φ = 13487001360.
The previous prime is 13487001247. The next prime is 13487001371. The reversal of 13487001361 is 16310078431.
13487001361 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13448808961 + 38192400 = 115969^2 + 6180^2 .
It is a cyclic number.
It is not a de Polignac number, because 13487001361 - 27 = 13487001233 is a prime.
It is not a weakly prime, because it can be changed into another prime (13487001371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6743500680 + 6743500681.
It is an arithmetic number, because the mean of its divisors is an integer number (6743500681).
Almost surely, 213487001361 is an apocalyptic number.
It is an amenable number.
13487001361 is a deficient number, since it is larger than the sum of its proper divisors (1).
13487001361 is an equidigital number, since it uses as much as digits as its factorization.
13487001361 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 34.
Adding to 13487001361 its reverse (16310078431), we get a palindrome (29797079792).
The spelling of 13487001361 in words is "thirteen billion, four hundred eighty-seven million, one thousand, three hundred sixty-one".
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