Base | Representation |
---|---|
bin | 10000000101010… |
… | …00000011000101 |
3 | 100101211221022111 |
4 | 20002220003011 |
5 | 234013443203 |
6 | 21215301021 |
7 | 3225453052 |
oct | 1002500305 |
9 | 311757274 |
10 | 134906053 |
11 | 6a172a07 |
12 | 3921a771 |
13 | 21c45889 |
14 | 13cba029 |
15 | bc9c26d |
hex | 80a80c5 |
134906053 has 2 divisors, whose sum is σ = 134906054. Its totient is φ = 134906052.
The previous prime is 134906021. The next prime is 134906059. The reversal of 134906053 is 350609431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97476129 + 37429924 = 9873^2 + 6118^2 .
It is a cyclic number.
It is not a de Polignac number, because 134906053 - 25 = 134906021 is a prime.
It is a super-3 number, since 3×1349060533 (a number of 25 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134906059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67453026 + 67453027.
It is an arithmetic number, because the mean of its divisors is an integer number (67453027).
Almost surely, 2134906053 is an apocalyptic number.
It is an amenable number.
134906053 is a deficient number, since it is larger than the sum of its proper divisors (1).
134906053 is an equidigital number, since it uses as much as digits as its factorization.
134906053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
The square root of 134906053 is about 11614.9064998389. The cubic root of 134906053 is about 512.8737585292.
The spelling of 134906053 in words is "one hundred thirty-four million, nine hundred six thousand, fifty-three".
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