1349106214181 has 16 divisors (see below), whose sum is σ = 1511588275008. Its totient is φ = 1193266080000.

The previous prime is 1349106214177. The next prime is 1349106214219. The reversal of 1349106214181 is 1814126019431.

It is a cyclic number.

It is not a de Polignac number, because 1349106214181 - 2² = 1349106214177 is a prime.

It is a super-2 number, since 2×1349106214181² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1349106294181) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14300141 + ... + 14394173.

It is an arithmetic number, because the mean of its divisors is an integer number (94474267188).

Almost surely, 2^{1349106214181} is an apocalyptic number.

1349106214181 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1349106214181 is a deficient number, since it is larger than the sum of its proper divisors (162482060827).

1349106214181 is a wasteful number, since it uses less digits than its factorization.

1349106214181 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129332.

The product of its (nonzero) digits is 41472, while the sum is 41.

The spelling of 1349106214181 in words is "one trillion, three hundred forty-nine billion, one hundred six million, two hundred fourteen thousand, one hundred eighty-one".