1349154431 has 2 divisors, whose sum is σ = 1349154432. Its totient is φ = 1349154430.

The previous prime is 1349154419. The next prime is 1349154463. The reversal of 1349154431 is 1344519431.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1349154431 is a prime.

It is a super-2 number, since 2×1349154431² = 3640435357373867522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1349154391 and 1349154400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1349154481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674577215 + 674577216.

It is an arithmetic number, because the mean of its divisors is an integer number (674577216).

Almost surely, 2^1349154431 is an apocalyptic number.

1349154431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1349154431 is an equidigital number, since it uses as much as digits as its factorization.

1349154431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25920, while the sum is 35.

The square root of 1349154431 is about 36730.8376027555. The cubic root of 1349154431 is about 1104.9786530413.

The spelling of 1349154431 in words is "one billion, three hundred forty-nine million, one hundred fifty-four thousand, four hundred thirty-one".