Base | Representation |
---|---|
bin | 101000001101011… |
… | …0000001111010101 |
3 | 10111000201222120201 |
4 | 1100122300033111 |
5 | 10230343044423 |
6 | 341513500501 |
7 | 45301634221 |
oct | 12032601725 |
9 | 3430658521 |
10 | 1349190613 |
11 | 632645971 |
12 | 317a11731 |
13 | 18669bb54 |
14 | cb287781 |
15 | 7d6aa2ad |
hex | 506b03d5 |
1349190613 has 2 divisors, whose sum is σ = 1349190614. Its totient is φ = 1349190612.
The previous prime is 1349190593. The next prime is 1349190637. The reversal of 1349190613 is 3160919431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1143927684 + 205262929 = 33822^2 + 14327^2 .
It is an emirp because it is prime and its reverse (3160919431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1349190613 - 25 = 1349190581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1349190673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674595306 + 674595307.
It is an arithmetic number, because the mean of its divisors is an integer number (674595307).
Almost surely, 21349190613 is an apocalyptic number.
It is an amenable number.
1349190613 is a deficient number, since it is larger than the sum of its proper divisors (1).
1349190613 is an equidigital number, since it uses as much as digits as its factorization.
1349190613 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 37.
The square root of 1349190613 is about 36731.3301283795. The cubic root of 1349190613 is about 1104.9885308283.
The spelling of 1349190613 in words is "one billion, three hundred forty-nine million, one hundred ninety thousand, six hundred thirteen".
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