Base | Representation |
---|---|
bin | 111110110101001000… |
… | …0110100010111110101 |
3 | 110220021021112121002012 |
4 | 1331222100310113311 |
5 | 4202312223424033 |
6 | 141552353054005 |
7 | 12514416464063 |
oct | 1755220642765 |
9 | 426237477065 |
10 | 134926779893 |
11 | 52249716854 |
12 | 22196857305 |
13 | c953807cc9 |
14 | 675d94b033 |
15 | 379a655248 |
hex | 1f6a4345f5 |
134926779893 has 2 divisors, whose sum is σ = 134926779894. Its totient is φ = 134926779892.
The previous prime is 134926779877. The next prime is 134926779929. The reversal of 134926779893 is 398977629431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 124890146404 + 10036633489 = 353398^2 + 100183^2 .
It is a cyclic number.
It is not a de Polignac number, because 134926779893 - 24 = 134926779877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134926779863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67463389946 + 67463389947.
It is an arithmetic number, because the mean of its divisors is an integer number (67463389947).
Almost surely, 2134926779893 is an apocalyptic number.
It is an amenable number.
134926779893 is a deficient number, since it is larger than the sum of its proper divisors (1).
134926779893 is an equidigital number, since it uses as much as digits as its factorization.
134926779893 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 123451776, while the sum is 68.
The spelling of 134926779893 in words is "one hundred thirty-four billion, nine hundred twenty-six million, seven hundred seventy-nine thousand, eight hundred ninety-three".
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