Base | Representation |
---|---|
bin | 10000000101011… |
… | …01011011110001 |
3 | 100101220001120112 |
4 | 20002231123301 |
5 | 234020144423 |
6 | 21215551105 |
7 | 3225604265 |
oct | 1002553361 |
9 | 311801515 |
10 | 134928113 |
11 | 6a188541 |
12 | 3922b495 |
13 | 21c52928 |
14 | 13cc40a5 |
15 | bca3a78 |
hex | 80ad6f1 |
134928113 has 2 divisors, whose sum is σ = 134928114. Its totient is φ = 134928112.
The previous prime is 134928107. The next prime is 134928127. The reversal of 134928113 is 311829431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 104203264 + 30724849 = 10208^2 + 5543^2 .
It is a cyclic number.
It is not a de Polignac number, because 134928113 - 26 = 134928049 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 134928113.
It is not a weakly prime, because it can be changed into another prime (134928173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67464056 + 67464057.
It is an arithmetic number, because the mean of its divisors is an integer number (67464057).
Almost surely, 2134928113 is an apocalyptic number.
It is an amenable number.
134928113 is a deficient number, since it is larger than the sum of its proper divisors (1).
134928113 is an equidigital number, since it uses as much as digits as its factorization.
134928113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 32.
The square root of 134928113 is about 11615.8561027588. The cubic root of 134928113 is about 512.9017122501.
The spelling of 134928113 in words is "one hundred thirty-four million, nine hundred twenty-eight thousand, one hundred thirteen".
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