13493531 has 2 divisors, whose sum is σ = 13493532. Its totient is φ = 13493530.

The previous prime is 13493521. The next prime is 13493533. The reversal of 13493531 is 13539431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13493531 - 2¹⁴ = 13477147 is a prime.

It is a super-2 number, since 2×13493531² = 364150757695922, which contains 22 as substring.

Together with 13493533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13493494 and 13493503.

It is not a weakly prime, because it can be changed into another prime (13493533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6746765 + 6746766.

It is an arithmetic number, because the mean of its divisors is an integer number (6746766).

Almost surely, 2^13493531 is an apocalyptic number.

13493531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13493531 is an equidigital number, since it uses as much as digits as its factorization.

13493531 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4860, while the sum is 29.

The square root of 13493531 is about 3673.3541892935. The cubic root of 13493531 is about 238.0721187653.

The spelling of 13493531 in words is "thirteen million, four hundred ninety-three thousand, five hundred thirty-one".