13494740953 has 4 divisors (see below), whose sum is σ = 13497475968. Its totient is φ = 13492005940.

The previous prime is 13494740939. The next prime is 13494740971. The reversal of 13494740953 is 35904749431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35904749431 = 137 ⋅262078463.

It is a cyclic number.

It is not a de Polignac number, because 13494740953 - 2²⁵ = 13461186521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13494740897 and 13494740906.

It is not an unprimeable number, because it can be changed into a prime (13494743953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1360093 + ... + 1369978.

It is an arithmetic number, because the mean of its divisors is an integer number (3374368992).

Almost surely, 2^13494740953 is an apocalyptic number.

It is an amenable number.

13494740953 is a deficient number, since it is larger than the sum of its proper divisors (2735015).

13494740953 is an equidigital number, since it uses as much as digits as its factorization.

13494740953 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2735014.

The product of its (nonzero) digits is 1632960, while the sum is 49.

The spelling of 13494740953 in words is "thirteen billion, four hundred ninety-four million, seven hundred forty thousand, nine hundred fifty-three".