Base | Representation |
---|---|
bin | 11001001000110000… |
… | …10100111111001001 |
3 | 1021211111201012012102 |
4 | 30210120110333021 |
5 | 210114241242311 |
6 | 10111042123145 |
7 | 655265544443 |
oct | 144430247711 |
9 | 37744635172 |
10 | 13495259081 |
11 | 57a57a3987 |
12 | 27476504b5 |
13 | 1370b86c05 |
14 | 920449493 |
15 | 53eb8043b |
hex | 324614fc9 |
13495259081 has 2 divisors, whose sum is σ = 13495259082. Its totient is φ = 13495259080.
The previous prime is 13495259053. The next prime is 13495259093. The reversal of 13495259081 is 18095259431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11862695056 + 1632564025 = 108916^2 + 40405^2 .
It is a cyclic number.
It is not a de Polignac number, because 13495259081 - 230 = 12421517257 is a prime.
It is a super-2 number, since 2×134952590812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13495259021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6747629540 + 6747629541.
It is an arithmetic number, because the mean of its divisors is an integer number (6747629541).
Almost surely, 213495259081 is an apocalyptic number.
It is an amenable number.
13495259081 is a deficient number, since it is larger than the sum of its proper divisors (1).
13495259081 is an equidigital number, since it uses as much as digits as its factorization.
13495259081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 47.
The spelling of 13495259081 in words is "thirteen billion, four hundred ninety-five million, two hundred fifty-nine thousand, eighty-one".
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