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13495259053 is a prime number
BaseRepresentation
bin11001001000110000…
…10100111110101101
31021211111201012011101
430210120110332231
5210114241242203
610111042123101
7655265544403
oct144430247655
937744635141
1013495259053
1157a57a3961
122747650491
131370b86bb3
14920449473
1553eb8041d
hex324614fad

13495259053 has 2 divisors, whose sum is σ = 13495259054. Its totient is φ = 13495259052.

The previous prime is 13495259021. The next prime is 13495259081. The reversal of 13495259053 is 35095259431.

13495259053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12099340009 + 1395919044 = 109997^2 + 37362^2 .

It is an emirp because it is prime and its reverse (35095259431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13495259053 - 25 = 13495259021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13495258994 and 13495259012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13495259003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6747629526 + 6747629527.

It is an arithmetic number, because the mean of its divisors is an integer number (6747629527).

Almost surely, 213495259053 is an apocalyptic number.

It is an amenable number.

13495259053 is a deficient number, since it is larger than the sum of its proper divisors (1).

13495259053 is an equidigital number, since it uses as much as digits as its factorization.

13495259053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 729000, while the sum is 46.

The spelling of 13495259053 in words is "thirteen billion, four hundred ninety-five million, two hundred fifty-nine thousand, fifty-three".