Base | Representation |
---|---|
bin | 1100010001100010000011… |
… | …0100011010101111010101 |
3 | 1202210010211022001210012102 |
4 | 3010120200310122233111 |
5 | 3232101422442342312 |
6 | 44411401141531445 |
7 | 2562002024041256 |
oct | 304304064325725 |
9 | 52703738053172 |
10 | 13495337855957 |
11 | 4333382440391 |
12 | 161b5a1413b85 |
13 | 76b7b2c6b079 |
14 | 34926bdb2b2d |
15 | 1860a0d4dec2 |
hex | c4620d1abd5 |
13495337855957 has 2 divisors, whose sum is σ = 13495337855958. Its totient is φ = 13495337855956.
The previous prime is 13495337855911. The next prime is 13495337856023. The reversal of 13495337855957 is 75955873359431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12855315455761 + 640022400196 = 3585431^2 + 800014^2 .
It is a cyclic number.
It is not a de Polignac number, because 13495337855957 - 212 = 13495337851861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13495337855257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6747668927978 + 6747668927979.
It is an arithmetic number, because the mean of its divisors is an integer number (6747668927979).
Almost surely, 213495337855957 is an apocalyptic number.
It is an amenable number.
13495337855957 is a deficient number, since it is larger than the sum of its proper divisors (1).
13495337855957 is an equidigital number, since it uses as much as digits as its factorization.
13495337855957 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2143260000, while the sum is 74.
The spelling of 13495337855957 in words is "thirteen trillion, four hundred ninety-five billion, three hundred thirty-seven million, eight hundred fifty-five thousand, nine hundred fifty-seven".
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