Base | Representation |
---|---|
bin | 10011101000110110100… |
… | …100100001000000101111 |
3 | 11210000101102201001021011 |
4 | 103220312210201000233 |
5 | 134102322012214012 |
6 | 2511545024250051 |
7 | 166333512360055 |
oct | 23506644410057 |
9 | 4700342631234 |
10 | 1349535273007 |
11 | 48037552aa49 |
12 | 199670770927 |
13 | 9a3507b217c |
14 | 494642a61d5 |
15 | 25187abd1a7 |
hex | 13a3692102f |
1349535273007 has 2 divisors, whose sum is σ = 1349535273008. Its totient is φ = 1349535273006.
The previous prime is 1349535272951. The next prime is 1349535273029. The reversal of 1349535273007 is 7003725359431.
It is a strong prime.
It is an emirp because it is prime and its reverse (7003725359431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1349535273007 - 215 = 1349535240239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1349535273607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674767636503 + 674767636504.
It is an arithmetic number, because the mean of its divisors is an integer number (674767636504).
Almost surely, 21349535273007 is an apocalyptic number.
1349535273007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1349535273007 is an equidigital number, since it uses as much as digits as its factorization.
1349535273007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2381400, while the sum is 49.
The spelling of 1349535273007 in words is "one trillion, three hundred forty-nine billion, five hundred thirty-five million, two hundred seventy-three thousand, seven".
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