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1349582707661 is a prime number
BaseRepresentation
bin10011101000111001011…
…001011101101111001101
311210000111201221222101012
4103220321121131233031
5134102421133121121
62511553441055005
7166334626511366
oct23507131355715
94700451858335
101349582707661
1148039a289341
12199684627465
139a35a57ca06
144946a6d2b6d
152518bd3cc5b
hex13a3965dbcd

1349582707661 has 2 divisors, whose sum is σ = 1349582707662. Its totient is φ = 1349582707660.

The previous prime is 1349582707631. The next prime is 1349582707771. The reversal of 1349582707661 is 1667072859431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 735975252100 + 613607455561 = 857890^2 + 783331^2 .

It is a cyclic number.

It is not a de Polignac number, because 1349582707661 - 26 = 1349582707597 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1349582707661.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1349582707631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 674791353830 + 674791353831.

It is an arithmetic number, because the mean of its divisors is an integer number (674791353831).

It is a 1-persistent number, because it is pandigital, but 2⋅1349582707661 = 2699165415322 is not.

Almost surely, 21349582707661 is an apocalyptic number.

It is an amenable number.

1349582707661 is a deficient number, since it is larger than the sum of its proper divisors (1).

1349582707661 is an equidigital number, since it uses as much as digits as its factorization.

1349582707661 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15240960, while the sum is 59.

The spelling of 1349582707661 in words is "one trillion, three hundred forty-nine billion, five hundred eighty-two million, seven hundred seven thousand, six hundred sixty-one".