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134959801 is a prime number
BaseRepresentation
bin10000000101101…
…01001010111001
3100101221200001011
420002311022321
5234022203201
621220353521
73226065544
oct1002651271
9311850034
10134959801
116a1aa329
12392458a1
1321c64192
1413cd185b
15bcad151
hex80b52b9

134959801 has 2 divisors, whose sum is σ = 134959802. Its totient is φ = 134959800.

The previous prime is 134959789. The next prime is 134959813. The reversal of 134959801 is 108959431.

It is a balanced prime because it is at equal distance from previous prime (134959789) and next prime (134959813).

It can be written as a sum of positive squares in only one way, i.e., 122877225 + 12082576 = 11085^2 + 3476^2 .

It is a cyclic number.

It is not a de Polignac number, because 134959801 - 27 = 134959673 is a prime.

It is a super-3 number, since 3×1349598013 (a number of 25 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (134959841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67479900 + 67479901.

It is an arithmetic number, because the mean of its divisors is an integer number (67479901).

Almost surely, 2134959801 is an apocalyptic number.

It is an amenable number.

134959801 is a deficient number, since it is larger than the sum of its proper divisors (1).

134959801 is an equidigital number, since it uses as much as digits as its factorization.

134959801 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 40.

The square root of 134959801 is about 11617.2200202975. The cubic root of 134959801 is about 512.9418609311.

The spelling of 134959801 in words is "one hundred thirty-four million, nine hundred fifty-nine thousand, eight hundred one".