Base | Representation |
---|---|
bin | 1100010001100110100010… |
… | …0011000110011010110111 |
3 | 1202210020221011111211220212 |
4 | 3010121220203012122313 |
5 | 3232111404031311311 |
6 | 44412120411220035 |
7 | 2562043605662105 |
oct | 304315043063267 |
9 | 52706834454825 |
10 | 13496541275831 |
11 | 433393a772569 |
12 | 161b87844761b |
13 | 76b94538c033 |
14 | 349343b52c75 |
15 | 186121812c8b |
hex | c46688c66b7 |
13496541275831 has 2 divisors, whose sum is σ = 13496541275832. Its totient is φ = 13496541275830.
The previous prime is 13496541275827. The next prime is 13496541275887. The reversal of 13496541275831 is 13857214569431.
It is a weak prime.
It is an emirp because it is prime and its reverse (13857214569431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13496541275831 - 22 = 13496541275827 is a prime.
It is a super-2 number, since 2×134965412758312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13496541275801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6748270637915 + 6748270637916.
It is an arithmetic number, because the mean of its divisors is an integer number (6748270637916).
Almost surely, 213496541275831 is an apocalyptic number.
13496541275831 is a deficient number, since it is larger than the sum of its proper divisors (1).
13496541275831 is an equidigital number, since it uses as much as digits as its factorization.
13496541275831 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21772800, while the sum is 59.
The spelling of 13496541275831 in words is "thirteen trillion, four hundred ninety-six billion, five hundred forty-one million, two hundred seventy-five thousand, eight hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •