Base | Representation |
---|---|
bin | 10000000101101… |
… | …10101100010011 |
3 | 100101221222121001 |
4 | 20002312230103 |
5 | 234022403120 |
6 | 21220442431 |
7 | 3226122661 |
oct | 1002665423 |
9 | 311858531 |
10 | 134966035 |
11 | 6a203a86 |
12 | 39249417 |
13 | 21c66c79 |
14 | 13cd3c31 |
15 | bcaee0a |
hex | 80b6b13 |
134966035 has 8 divisors (see below), whose sum is σ = 165726000. Its totient is φ = 105461664.
The previous prime is 134966023. The next prime is 134966053. The reversal of 134966035 is 530669431.
134966035 = 12102 + 12112 + ... + 12952.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 134966035 - 25 = 134966003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134965985 and 134966003.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 313660 + ... + 314089.
It is an arithmetic number, because the mean of its divisors is an integer number (20715750).
Almost surely, 2134966035 is an apocalyptic number.
134966035 is a deficient number, since it is larger than the sum of its proper divisors (30759965).
134966035 is an equidigital number, since it uses as much as digits as its factorization.
134966035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 627797.
The product of its (nonzero) digits is 58320, while the sum is 37.
The square root of 134966035 is about 11617.4883257957. The cubic root of 134966035 is about 512.9497586664.
The spelling of 134966035 in words is "one hundred thirty-four million, nine hundred sixty-six thousand, thirty-five".
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