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13499253967249 is a prime number
BaseRepresentation
bin1100010001110000101000…
…1111001100100110010001
31202210111221012220211222101
43010130022033030212101
53232132433003422444
644413245513440401
72562201045324331
oct304341217144621
952714835824871
1013499253967249
114335001a377a6
1216202b4a10101
1376bc8839a39b
1434952012b0c1
1518622ea533d4
hexc470a3cc991

13499253967249 has 2 divisors, whose sum is σ = 13499253967250. Its totient is φ = 13499253967248.

The previous prime is 13499253967237. The next prime is 13499253967261. The reversal of 13499253967249 is 94276935299431.

It is a balanced prime because it is at equal distance from previous prime (13499253967237) and next prime (13499253967261).

It can be written as a sum of positive squares in only one way, i.e., 13380086094400 + 119167872849 = 3657880^2 + 345207^2 .

It is a cyclic number.

It is not a de Polignac number, because 13499253967249 - 235 = 13464894228881 is a prime.

It is not a weakly prime, because it can be changed into another prime (13499253967049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6749626983624 + 6749626983625.

It is an arithmetic number, because the mean of its divisors is an integer number (6749626983625).

Almost surely, 213499253967249 is an apocalyptic number.

It is an amenable number.

13499253967249 is a deficient number, since it is larger than the sum of its proper divisors (1).

13499253967249 is an equidigital number, since it uses as much as digits as its factorization.

13499253967249 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 793618560, while the sum is 73.

The spelling of 13499253967249 in words is "thirteen trillion, four hundred ninety-nine billion, two hundred fifty-three million, nine hundred sixty-seven thousand, two hundred forty-nine".