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13499447980032 = 2123372172931163
BaseRepresentation
bin1100010001110001010111…
…0011010011000000000000
31202210112102201222201111000
43010130111303103000000
53232133332140330112
644413321044052000
72562205622364300
oct304342563230000
952715381881430
1013499447980032
1143350a1500443
121620349994000
1376bcb9639451
1434953bbd1600
15186241ac87dc
hexc4715cd3000

13499447980032 has 2496 divisors, whose sum is σ = 52924816281600. Its totient is φ = 3371056496640.

The previous prime is 13499447980013. The next prime is 13499447980111. The reversal of 13499447980032 is 23008974499431.

13499447980032 is a `hidden beast` number, since 1 + 3 + 49 + 94 + 479 + 8 + 0 + 0 + 32 = 666.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 82818699183 + ... + 82818699345.

Almost surely, 213499447980032 is an apocalyptic number.

13499447980032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13499447980032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26462408140800).

13499447980032 is an abundant number, since it is smaller than the sum of its proper divisors (39425368301568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13499447980032 is a wasteful number, since it uses less digits than its factorization.

13499447980032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 287 (or 252 counting only the distinct ones).

The product of its (nonzero) digits is 47029248, while the sum is 63.

The spelling of 13499447980032 in words is "thirteen trillion, four hundred ninety-nine billion, four hundred forty-seven million, nine hundred eighty thousand, thirty-two".