Base | Representation |
---|---|
bin | 11001001001010101… |
… | …00111011110011001 |
3 | 1021211211201202202211 |
4 | 30210222213132121 |
5 | 210122003202101 |
6 | 10111332555121 |
7 | 655354363162 |
oct | 144452473631 |
9 | 37754652684 |
10 | 13500053401 |
11 | 57a8478a2a |
12 | 2749182aa1 |
13 | 1371b751a3 |
14 | 920d36769 |
15 | 5402cac51 |
hex | 324aa7799 |
13500053401 has 2 divisors, whose sum is σ = 13500053402. Its totient is φ = 13500053400.
The previous prime is 13500053351. The next prime is 13500053419. The reversal of 13500053401 is 10435000531.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12328771225 + 1171282176 = 111035^2 + 34224^2 .
It is an emirp because it is prime and its reverse (10435000531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13500053401 - 29 = 13500052889 is a prime.
It is not a weakly prime, because it can be changed into another prime (13500053431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750026700 + 6750026701.
It is an arithmetic number, because the mean of its divisors is an integer number (6750026701).
Almost surely, 213500053401 is an apocalyptic number.
It is an amenable number.
13500053401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13500053401 is an equidigital number, since it uses as much as digits as its factorization.
13500053401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 22.
Adding to 13500053401 its reverse (10435000531), we get a palindrome (23935053932).
The spelling of 13500053401 in words is "thirteen billion, five hundred million, fifty-three thousand, four hundred one".
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