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13500053401 is a prime number
BaseRepresentation
bin11001001001010101…
…00111011110011001
31021211211201202202211
430210222213132121
5210122003202101
610111332555121
7655354363162
oct144452473631
937754652684
1013500053401
1157a8478a2a
122749182aa1
131371b751a3
14920d36769
155402cac51
hex324aa7799

13500053401 has 2 divisors, whose sum is σ = 13500053402. Its totient is φ = 13500053400.

The previous prime is 13500053351. The next prime is 13500053419. The reversal of 13500053401 is 10435000531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12328771225 + 1171282176 = 111035^2 + 34224^2 .

It is an emirp because it is prime and its reverse (10435000531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13500053401 - 29 = 13500052889 is a prime.

It is not a weakly prime, because it can be changed into another prime (13500053431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750026700 + 6750026701.

It is an arithmetic number, because the mean of its divisors is an integer number (6750026701).

Almost surely, 213500053401 is an apocalyptic number.

It is an amenable number.

13500053401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13500053401 is an equidigital number, since it uses as much as digits as its factorization.

13500053401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 900, while the sum is 22.

Adding to 13500053401 its reverse (10435000531), we get a palindrome (23935053932).

The spelling of 13500053401 in words is "thirteen billion, five hundred million, fifty-three thousand, four hundred one".