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13500251301151 = 193154087453961
BaseRepresentation
bin1100010001110100010110…
…1011101110010100011111
31202210121111201120122220001
43010131011223232110133
53232142003313114101
644413532502035131
72562234545452336
oct304350553562437
952717451518801
1013500251301151
1143354739aa49a
121620532a18aa7
1376c0b6bb2ba4
143495b6782d1d
1518628c3a9901
hexc4745aee51f

13500251301151 has 8 divisors (see below), whose sum is σ = 13570318751264. Its totient is φ = 13430185067520.

The previous prime is 13500251301137. The next prime is 13500251301157. The reversal of 13500251301151 is 15110315200531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13500251301151 - 27 = 13500251301023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13500251301157) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29511811 + ... + 29965771.

It is an arithmetic number, because the mean of its divisors is an integer number (1696289843908).

Almost surely, 213500251301151 is an apocalyptic number.

13500251301151 is a deficient number, since it is larger than the sum of its proper divisors (70067450113).

13500251301151 is a wasteful number, since it uses less digits than its factorization.

13500251301151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 608241.

The product of its (nonzero) digits is 2250, while the sum is 28.

Adding to 13500251301151 its reverse (15110315200531), we get a palindrome (28610566501682).

The spelling of 13500251301151 in words is "thirteen trillion, five hundred billion, two hundred fifty-one million, three hundred one thousand, one hundred fifty-one".

Divisors: 1 193 154087 453961 29738791 87614473 69949488607 13500251301151