Base | Representation |
---|---|
bin | 1100010001110100010110… |
… | …1011101110010100011111 |
3 | 1202210121111201120122220001 |
4 | 3010131011223232110133 |
5 | 3232142003313114101 |
6 | 44413532502035131 |
7 | 2562234545452336 |
oct | 304350553562437 |
9 | 52717451518801 |
10 | 13500251301151 |
11 | 43354739aa49a |
12 | 1620532a18aa7 |
13 | 76c0b6bb2ba4 |
14 | 3495b6782d1d |
15 | 18628c3a9901 |
hex | c4745aee51f |
13500251301151 has 8 divisors (see below), whose sum is σ = 13570318751264. Its totient is φ = 13430185067520.
The previous prime is 13500251301137. The next prime is 13500251301157. The reversal of 13500251301151 is 15110315200531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13500251301151 - 27 = 13500251301023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13500251301157) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29511811 + ... + 29965771.
It is an arithmetic number, because the mean of its divisors is an integer number (1696289843908).
Almost surely, 213500251301151 is an apocalyptic number.
13500251301151 is a deficient number, since it is larger than the sum of its proper divisors (70067450113).
13500251301151 is a wasteful number, since it uses less digits than its factorization.
13500251301151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 608241.
The product of its (nonzero) digits is 2250, while the sum is 28.
Adding to 13500251301151 its reverse (15110315200531), we get a palindrome (28610566501682).
The spelling of 13500251301151 in words is "thirteen trillion, five hundred billion, two hundred fifty-one million, three hundred one thousand, one hundred fifty-one".
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