Base | Representation |
---|---|
bin | 1100010001110100101100… |
… | …1111010101001001111111 |
3 | 1202210121202012222201221202 |
4 | 3010131023033111021333 |
5 | 3232142201144140333 |
6 | 44413550032050115 |
7 | 2562240060016331 |
oct | 304351317251177 |
9 | 52717665881852 |
10 | 13500344521343 |
11 | 4335511590179 |
12 | 162055a09393b |
13 | 76c1002c1774 |
14 | 3495c4ccb451 |
15 | 1862956705e8 |
hex | c474b3d527f |
13500344521343 has 2 divisors, whose sum is σ = 13500344521344. Its totient is φ = 13500344521342.
The previous prime is 13500344521319. The next prime is 13500344521379. The reversal of 13500344521343 is 34312544300531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13500344521343 - 228 = 13500076085887 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 13500344521297 and 13500344521306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13500344521043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750172260671 + 6750172260672.
It is an arithmetic number, because the mean of its divisors is an integer number (6750172260672).
Almost surely, 213500344521343 is an apocalyptic number.
13500344521343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13500344521343 is an equidigital number, since it uses as much as digits as its factorization.
13500344521343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 13500344521343 its reverse (34312544300531), we get a palindrome (47812888821874).
The spelling of 13500344521343 in words is "thirteen trillion, five hundred billion, three hundred forty-four million, five hundred twenty-one thousand, three hundred forty-three".
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