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1350040151 = 6720149853
BaseRepresentation
bin101000001110111…
…1111101001010111
310111002100010221002
41100131333221113
510231102241101
6341544013515
745312103055
oct12035775127
93432303832
101350040151
11633076169
1231816129b
13186908735
14cb4291d5
157d7c6d6b
hex5077fa57

1350040151 has 4 divisors (see below), whose sum is σ = 1370190072. Its totient is φ = 1329890232.

The previous prime is 1350040093. The next prime is 1350040163. The reversal of 1350040151 is 1510400531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1350040151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350040651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10074860 + ... + 10074993.

It is an arithmetic number, because the mean of its divisors is an integer number (342547518).

Almost surely, 21350040151 is an apocalyptic number.

1350040151 is a deficient number, since it is larger than the sum of its proper divisors (20149921).

1350040151 is an equidigital number, since it uses as much as digits as its factorization.

1350040151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20149920.

The product of its (nonzero) digits is 300, while the sum is 20.

The square root of 1350040151 is about 36742.8925235888. The cubic root of 1350040151 is about 1105.2204063390.

Adding to 1350040151 its reverse (1510400531), we get a palindrome (2860440682).

The spelling of 1350040151 in words is "one billion, three hundred fifty million, forty thousand, one hundred fifty-one".

Divisors: 1 67 20149853 1350040151