Search a number
-
+
1350050104311 = 3450016701437
BaseRepresentation
bin10011101001010101010…
…000011100001111110111
311210001201022110012001020
4103221111100130033313
5134104400311314221
62512112055032223
7166352333355006
oct23512520341767
94701638405036
101350050104311
1148060a0a7367
1219979506b673
139a40335ab8c
14494b27dcc3d
15251b7db5ac6
hex13a5541c3f7

1350050104311 has 4 divisors (see below), whose sum is σ = 1800066805752. Its totient is φ = 900033402872.

The previous prime is 1350050104213. The next prime is 1350050104313. The reversal of 1350050104311 is 1134010500531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1350050104311 - 214 = 1350050087927 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350050104313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225008350716 + ... + 225008350721.

It is an arithmetic number, because the mean of its divisors is an integer number (450016701438).

Almost surely, 21350050104311 is an apocalyptic number.

1350050104311 is a deficient number, since it is larger than the sum of its proper divisors (450016701441).

1350050104311 is an equidigital number, since it uses as much as digits as its factorization.

1350050104311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 450016701440.

The product of its (nonzero) digits is 900, while the sum is 24.

Adding to 1350050104311 its reverse (1134010500531), we get a palindrome (2484060604842).

The spelling of 1350050104311 in words is "one trillion, three hundred fifty billion, fifty million, one hundred four thousand, three hundred eleven".

Divisors: 1 3 450016701437 1350050104311