Base | Representation |
---|---|
bin | 11110101100100101010110… |
… | …000110000101101101011111 |
3 | 122201000100220010111021211111 |
4 | 132230211112012011231133 |
5 | 120143411022232430444 |
6 | 1155044302124002451 |
7 | 40302541336116253 |
oct | 3654452606055537 |
9 | 581010803437744 |
10 | 135005151451999 |
11 | 3a0203aa465934 |
12 | 13184aa0090427 |
13 | 5a43c14994aaa |
14 | 254a3d9b8c263 |
15 | 1091bd918b234 |
hex | 7ac956185b5f |
135005151451999 has 2 divisors, whose sum is σ = 135005151452000. Its totient is φ = 135005151451998.
The previous prime is 135005151451981. The next prime is 135005151452027. The reversal of 135005151451999 is 999154151500531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135005151451999 - 25 = 135005151451967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135005151451939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67502575725999 + 67502575726000.
It is an arithmetic number, because the mean of its divisors is an integer number (67502575726000).
Almost surely, 2135005151451999 is an apocalyptic number.
135005151451999 is a deficient number, since it is larger than the sum of its proper divisors (1).
135005151451999 is an equidigital number, since it uses as much as digits as its factorization.
135005151451999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5467500, while the sum is 58.
The spelling of 135005151451999 in words is "one hundred thirty-five trillion, five billion, one hundred fifty-one million, four hundred fifty-one thousand, nine hundred ninety-nine".
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