Base | Representation |
---|---|
bin | 11110101100100101100100… |
… | …111100010000110100001111 |
3 | 122201000101112111011222111102 |
4 | 132230211210330100310033 |
5 | 120143412030014044122 |
6 | 1155044342542413315 |
7 | 40302550452226553 |
oct | 3654454474206417 |
9 | 581011474158442 |
10 | 135005400534287 |
11 | 3a020518022068 |
12 | 13184b4b59123b |
13 | 5a43c5447586a |
14 | 254a420ca9863 |
15 | 1091c00e8d492 |
hex | 7ac964f10d0f |
135005400534287 has 2 divisors, whose sum is σ = 135005400534288. Its totient is φ = 135005400534286.
The previous prime is 135005400534271. The next prime is 135005400534311. The reversal of 135005400534287 is 782435004500531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135005400534287 - 24 = 135005400534271 is a prime.
It is a super-3 number, since 3×1350054005342873 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135005400534217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67502700267143 + 67502700267144.
It is an arithmetic number, because the mean of its divisors is an integer number (67502700267144).
Almost surely, 2135005400534287 is an apocalyptic number.
135005400534287 is a deficient number, since it is larger than the sum of its proper divisors (1).
135005400534287 is an equidigital number, since it uses as much as digits as its factorization.
135005400534287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016000, while the sum is 47.
The spelling of 135005400534287 in words is "one hundred thirty-five trillion, five billion, four hundred million, five hundred thirty-four thousand, two hundred eighty-seven".
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