Base | Representation |
---|---|
bin | 10011101001010110010… |
… | …010010110011000001011 |
3 | 11210001202111221222021011 |
4 | 103221112102112120023 |
5 | 134104414222204041 |
6 | 2512113513224351 |
7 | 166352633254423 |
oct | 23512622263013 |
9 | 4701674858234 |
10 | 1350067381771 |
11 | 480618928159 |
12 | 19979aa020b7 |
13 | 9a406aca024 |
14 | 494b4c19483 |
15 | 251b9679e81 |
hex | 13a5649660b |
1350067381771 has 2 divisors, whose sum is σ = 1350067381772. Its totient is φ = 1350067381770.
The previous prime is 1350067381757. The next prime is 1350067381777. The reversal of 1350067381771 is 1771837600531.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1350067381771 - 221 = 1350065284619 is a prime.
It is not a weakly prime, because it can be changed into another prime (1350067381777) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675033690885 + 675033690886.
It is an arithmetic number, because the mean of its divisors is an integer number (675033690886).
Almost surely, 21350067381771 is an apocalyptic number.
1350067381771 is a deficient number, since it is larger than the sum of its proper divisors (1).
1350067381771 is an equidigital number, since it uses as much as digits as its factorization.
1350067381771 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 740880, while the sum is 49.
The spelling of 1350067381771 in words is "one trillion, three hundred fifty billion, sixty-seven million, three hundred eighty-one thousand, seven hundred seventy-one".
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