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1350104003143 = 72232417357839
BaseRepresentation
bin10011101001011000011…
…110000011001001000111
311210001212001212112100021
4103221120132003021013
5134110003111100033
62512121302200011
7166353556451320
oct23513036031107
94701761775307
101350104003143
11480637570355
121997ab123007
139a41157ca8c
14494b9a2d447
15251bc9b0b2d
hex13a58783247

1350104003143 has 16 divisors (see below), whose sum is σ = 1550540759040. Its totient is φ = 1151562761856.

The previous prime is 1350104003057. The next prime is 1350104003167. The reversal of 1350104003143 is 3413004010531.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1350104003143 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350104004143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3594018 + ... + 3951856.

It is an arithmetic number, because the mean of its divisors is an integer number (96908797440).

Almost surely, 21350104003143 is an apocalyptic number.

1350104003143 is a deficient number, since it is larger than the sum of its proper divisors (200436755897).

1350104003143 is a wasteful number, since it uses less digits than its factorization.

1350104003143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 360486.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 1350104003143 its reverse (3413004010531), we get a palindrome (4763108013674).

The spelling of 1350104003143 in words is "one trillion, three hundred fifty billion, one hundred four million, three thousand, one hundred forty-three".

Divisors: 1 7 223 1561 2417 16919 357839 538991 2504873 3772937 79798097 558586679 864896863 6054278041 192872000449 1350104003143