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1350120353 = 3114341223
BaseRepresentation
bin101000001111001…
…0011001110100001
310111002111012221112
41100132103032201
510231112322403
6341545433105
745312555641
oct12036231641
93432435845
101350120353
1163312044a
1231819b795
131869360aa
14cb44a521
157d7e09d8
hex507933a1

1350120353 has 4 divisors (see below), whose sum is σ = 1354461888. Its totient is φ = 1345778820.

The previous prime is 1350120347. The next prime is 1350120383. The reversal of 1350120353 is 3530210531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1350120353 - 24 = 1350120337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1350120323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170301 + ... + 2170922.

It is an arithmetic number, because the mean of its divisors is an integer number (338615472).

Almost surely, 21350120353 is an apocalyptic number.

It is an amenable number.

1350120353 is a deficient number, since it is larger than the sum of its proper divisors (4341535).

1350120353 is an equidigital number, since it uses as much as digits as its factorization.

1350120353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4341534.

The product of its (nonzero) digits is 1350, while the sum is 23.

The square root of 1350120353 is about 36743.9839021302. The cubic root of 1350120353 is about 1105.2422918934.

Adding to 1350120353 its reverse (3530210531), we get a palindrome (4880330884).

The spelling of 1350120353 in words is "one billion, three hundred fifty million, one hundred twenty thousand, three hundred fifty-three".

Divisors: 1 311 4341223 1350120353