Base | Representation |
---|---|
bin | 1100010001111000000101… |
… | …1001010101101010111011 |
3 | 1202210201002112200001112012 |
4 | 3010132001121111222323 |
5 | 3232201031244131210 |
6 | 44414220130240135 |
7 | 2562301431645203 |
oct | 304360131255273 |
9 | 52721075601465 |
10 | 13501253114555 |
11 | 4335938451758 |
12 | 162077242604b |
13 | 76c21660659b |
14 | 34966d843403 |
15 | 1862ea2e8305 |
hex | c4781655abb |
13501253114555 has 16 divisors (see below), whose sum is σ = 16561136845440. Its totient is φ = 10561661538432.
The previous prime is 13501253114551. The next prime is 13501253114581. The reversal of 13501253114555 is 55541135210531.
It is a happy number.
13501253114555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13501253114555 - 22 = 13501253114551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13501253114551) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25642064 + ... + 26163293.
It is an arithmetic number, because the mean of its divisors is an integer number (1035071052840).
Almost surely, 213501253114555 is an apocalyptic number.
13501253114555 is a deficient number, since it is larger than the sum of its proper divisors (3059883730885).
13501253114555 is a wasteful number, since it uses less digits than its factorization.
13501253114555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51806518.
The product of its (nonzero) digits is 225000, while the sum is 41.
The spelling of 13501253114555 in words is "thirteen trillion, five hundred one billion, two hundred fifty-three million, one hundred fourteen thousand, five hundred fifty-five".
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