13501325031 has 4 divisors (see below), whose sum is σ = 18001766712. Its totient is φ = 9000883352.

The previous prime is 13501325011. The next prime is 13501325039. The reversal of 13501325031 is 13052310531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13501325031 - 2¹⁰ = 13501324007 is a prime.

It is a super-2 number, since 2×13501325031² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13501324992 and 13501325010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13501325039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2250220836 + ... + 2250220841.

It is an arithmetic number, because the mean of its divisors is an integer number (4500441678).

Almost surely, 2^13501325031 is an apocalyptic number.

13501325031 is a deficient number, since it is larger than the sum of its proper divisors (4500441681).

13501325031 is an equidigital number, since it uses as much as digits as its factorization.

13501325031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4500441680.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 13501325031 its reverse (13052310531), we get a palindrome (26553635562).

The spelling of 13501325031 in words is "thirteen billion, five hundred one million, three hundred twenty-five thousand, thirty-one".