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13501453504435 = 513628273306137
BaseRepresentation
bin1100010001111000110101…
…0101110000111110110011
31202210201121111201220202121
43010132031111300332303
53232201434044120220
644414252045255111
72562306414145231
oct304361525607663
952721544656677
1013501453504435
114335a30580626
121620809564497
1376c248c99190
1434968c2c7951
1518630cbcceaa
hexc478d570fb3

13501453504435 has 16 divisors (see below), whose sum is σ = 17448315214176. Its totient is φ = 9970142416128.

The previous prime is 13501453504433. The next prime is 13501453504621. The reversal of 13501453504435 is 53440535410531.

It is a cyclic number.

It is not a de Polignac number, because 13501453504435 - 21 = 13501453504433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13501453504391 and 13501453504400.

It is not an unprimeable number, because it can be changed into a prime (13501453504433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2430687 + ... + 5736823.

It is an arithmetic number, because the mean of its divisors is an integer number (1090519700886).

Almost surely, 213501453504435 is an apocalyptic number.

13501453504435 is a deficient number, since it is larger than the sum of its proper divisors (3946861709741).

13501453504435 is a wasteful number, since it uses less digits than its factorization.

13501453504435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3368982.

The product of its (nonzero) digits is 1080000, while the sum is 43.

Adding to 13501453504435 its reverse (53440535410531), we get a palindrome (66941988914966).

The spelling of 13501453504435 in words is "thirteen trillion, five hundred one billion, four hundred fifty-three million, five hundred four thousand, four hundred thirty-five".

Divisors: 1 5 13 65 62827 314135 816751 3306137 4083755 16530685 42979781 214898905 207714669299 1038573346495 2700290700887 13501453504435