Base | Representation |
---|---|
bin | 1100010001111000110101… |
… | …0101110000111110110011 |
3 | 1202210201121111201220202121 |
4 | 3010132031111300332303 |
5 | 3232201434044120220 |
6 | 44414252045255111 |
7 | 2562306414145231 |
oct | 304361525607663 |
9 | 52721544656677 |
10 | 13501453504435 |
11 | 4335a30580626 |
12 | 1620809564497 |
13 | 76c248c99190 |
14 | 34968c2c7951 |
15 | 18630cbcceaa |
hex | c478d570fb3 |
13501453504435 has 16 divisors (see below), whose sum is σ = 17448315214176. Its totient is φ = 9970142416128.
The previous prime is 13501453504433. The next prime is 13501453504621. The reversal of 13501453504435 is 53440535410531.
It is a cyclic number.
It is not a de Polignac number, because 13501453504435 - 21 = 13501453504433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13501453504391 and 13501453504400.
It is not an unprimeable number, because it can be changed into a prime (13501453504433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2430687 + ... + 5736823.
It is an arithmetic number, because the mean of its divisors is an integer number (1090519700886).
Almost surely, 213501453504435 is an apocalyptic number.
13501453504435 is a deficient number, since it is larger than the sum of its proper divisors (3946861709741).
13501453504435 is a wasteful number, since it uses less digits than its factorization.
13501453504435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3368982.
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 13501453504435 its reverse (53440535410531), we get a palindrome (66941988914966).
The spelling of 13501453504435 in words is "thirteen trillion, five hundred one billion, four hundred fifty-three million, five hundred four thousand, four hundred thirty-five".
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