13501616113 has 4 divisors (see below), whose sum is σ = 13502633328. Its totient is φ = 13500598900.

The previous prime is 13501616099. The next prime is 13501616119. The reversal of 13501616113 is 31161610531.

13501616113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31161610531 = 43 ⋅724688617.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13501616113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13501616119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 488431 + ... + 515332.

It is an arithmetic number, because the mean of its divisors is an integer number (3375658332).

Almost surely, 2^13501616113 is an apocalyptic number.

It is an amenable number.

13501616113 is a deficient number, since it is larger than the sum of its proper divisors (1017215).

13501616113 is a wasteful number, since it uses less digits than its factorization.

13501616113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1017214.

The product of its (nonzero) digits is 1620, while the sum is 28.

The spelling of 13501616113 in words is "thirteen billion, five hundred one million, six hundred sixteen thousand, one hundred thirteen".