Base | Representation |
---|---|
bin | 11001001001100101… |
… | …00010111100110111 |
3 | 1021211222122101002211 |
4 | 30210302202330313 |
5 | 210123021211043 |
6 | 10111445314251 |
7 | 655411141252 |
oct | 144462427467 |
9 | 37758571084 |
10 | 13502132023 |
11 | 57a96686a6 |
12 | 2749a05987 |
13 | 1372422343 |
14 | 921318099 |
15 | 54058ba9d |
hex | 324ca2f37 |
13502132023 has 2 divisors, whose sum is σ = 13502132024. Its totient is φ = 13502132022.
The previous prime is 13502132009. The next prime is 13502132027. The reversal of 13502132023 is 32023120531.
It is a strong prime.
It is an emirp because it is prime and its reverse (32023120531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13502132023 - 221 = 13500034871 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13502131985 and 13502132003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13502132027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751066011 + 6751066012.
It is an arithmetic number, because the mean of its divisors is an integer number (6751066012).
Almost surely, 213502132023 is an apocalyptic number.
13502132023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13502132023 is an equidigital number, since it uses as much as digits as its factorization.
13502132023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 22.
Adding to 13502132023 its reverse (32023120531), we get a palindrome (45525252554).
The spelling of 13502132023 in words is "thirteen billion, five hundred two million, one hundred thirty-two thousand, twenty-three".
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