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1350256124251 is a prime number
BaseRepresentation
bin10011101001100001100…
…010010110000101011011
311210002020200010002021101
4103221201202112011123
5134110311031434001
62512144334452231
7166360414454146
oct23514142260533
94702220102241
101350256124251
11480705421181
12199832064077
139a436c42278
14494d1d0b05d
15251cb00da01
hex13a6189615b

1350256124251 has 2 divisors, whose sum is σ = 1350256124252. Its totient is φ = 1350256124250.

The previous prime is 1350256124249. The next prime is 1350256124267. The reversal of 1350256124251 is 1524216520531.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1350256124251 - 21 = 1350256124249 is a prime.

It is a super-2 number, since 2×13502561242512 (a number of 25 digits) contains 22 as substring.

Together with 1350256124249, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1350256124251.

It is not a weakly prime, because it can be changed into another prime (1350256124201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675128062125 + 675128062126.

It is an arithmetic number, because the mean of its divisors is an integer number (675128062126).

Almost surely, 21350256124251 is an apocalyptic number.

1350256124251 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350256124251 is an equidigital number, since it uses as much as digits as its factorization.

1350256124251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 37.

The spelling of 1350256124251 in words is "one trillion, three hundred fifty billion, two hundred fifty-six million, one hundred twenty-four thousand, two hundred fifty-one".