1350320300031 has 4 divisors (see below), whose sum is σ = 1800427066712. Its totient is φ = 900213533352.

The previous prime is 1350320300029. The next prime is 1350320300041. The reversal of 1350320300031 is 1300030230531.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1350320300031 - 2¹ = 1350320300029 is a prime.

It is a super-2 number, since 2×1350320300031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1350320299980 and 1350320300007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1350320300041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225053383336 + ... + 225053383341.

It is an arithmetic number, because the mean of its divisors is an integer number (450106766678).

Almost surely, 2^{1350320300031} is an apocalyptic number.

1350320300031 is a deficient number, since it is larger than the sum of its proper divisors (450106766681).

1350320300031 is an equidigital number, since it uses as much as digits as its factorization.

1350320300031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450106766680.

The product of its (nonzero) digits is 810, while the sum is 21.

Adding to 1350320300031 its reverse (1300030230531), we get a palindrome (2650350530562).

The spelling of 1350320300031 in words is "one trillion, three hundred fifty billion, three hundred twenty million, three hundred thousand, thirty-one".