Base | Representation |
---|---|
bin | 11110101100111110011000… |
… | …011010111000110010100100 |
3 | 122201002221021121202102200111 |
4 | 132230332120122320302210 |
5 | 120144331101201113012 |
6 | 1155104505434222404 |
7 | 40304512453050646 |
oct | 3654763032706244 |
9 | 581087247672614 |
10 | 135032034004132 |
11 | 3a030844a10171 |
12 | 1318a142b84a04 |
13 | 5a4660a233285 |
14 | 254b82a17a896 |
15 | 109275e271ba7 |
hex | 7acf986b8ca4 |
135032034004132 has 6 divisors (see below), whose sum is σ = 236306059507238. Its totient is φ = 67516017002064.
The previous prime is 135032034004111. The next prime is 135032034004207. The reversal of 135032034004132 is 231400430230531.
It is a happy number.
It can be written as a sum of positive squares in only one way, i.e., 113480954729536 + 21551079274596 = 10652744^2 + 4642314^2 .
It is a junction number, because it is equal to n+sod(n) for n = 135032034004094 and 135032034004103.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16879004250513 + ... + 16879004250520.
Almost surely, 2135032034004132 is an apocalyptic number.
It is an amenable number.
135032034004132 is a deficient number, since it is larger than the sum of its proper divisors (101274025503106).
135032034004132 is a wasteful number, since it uses less digits than its factorization.
135032034004132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33758008501037 (or 33758008501035 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 135032034004132 its reverse (231400430230531), we get a palindrome (366432464234663).
The spelling of 135032034004132 in words is "one hundred thirty-five trillion, thirty-two billion, thirty-four million, four thousand, one hundred thirty-two".
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