Base | Representation |
---|---|
bin | 111110111000010001… |
… | …1111011100001111011 |
3 | 110220112122101100122222 |
4 | 1331300203323201323 |
5 | 4203021302000433 |
6 | 142011050034255 |
7 | 12520141625462 |
oct | 1756043734173 |
9 | 426478340588 |
10 | 135032453243 |
11 | 522a33327a6 |
12 | 2220611898b |
13 | c96c686c0c |
14 | 676d9b79d9 |
15 | 37a4a7ab98 |
hex | 1f708fb87b |
135032453243 has 2 divisors, whose sum is σ = 135032453244. Its totient is φ = 135032453242.
The previous prime is 135032453219. The next prime is 135032453249. The reversal of 135032453243 is 342354230531.
It is a strong prime.
It is an emirp because it is prime and its reverse (342354230531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135032453243 - 28 = 135032452987 is a prime.
It is not a weakly prime, because it can be changed into another prime (135032453249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67516226621 + 67516226622.
It is an arithmetic number, because the mean of its divisors is an integer number (67516226622).
Almost surely, 2135032453243 is an apocalyptic number.
135032453243 is a deficient number, since it is larger than the sum of its proper divisors (1).
135032453243 is an equidigital number, since it uses as much as digits as its factorization.
135032453243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 135032453243 its reverse (342354230531), we get a palindrome (477386683774).
The spelling of 135032453243 in words is "one hundred thirty-five billion, thirty-two million, four hundred fifty-three thousand, two hundred forty-three".
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