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13503304155145 = 57385808690147
BaseRepresentation
bin1100010001111111101110…
…1001011100000000001001
31202210220101111001201021111
43010133323221130000021
53232214231330431040
644415155435210321
72562403315340320
oct304377351340011
952726344051244
1013503304155145
1143367a018a922
1216210452a69a1
1376c48251187c
143497c5dc70b7
151863ba3dddea
hexc47fba5c009

13503304155145 has 8 divisors (see below), whose sum is σ = 18518817127104. Its totient is φ = 9259408563504.

The previous prime is 13503304155137. The next prime is 13503304155151. The reversal of 13503304155145 is 54155140330531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13503304155145 - 23 = 13503304155137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13503304155098 and 13503304155107.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 192904345039 + ... + 192904345108.

It is an arithmetic number, because the mean of its divisors is an integer number (2314852140888).

Almost surely, 213503304155145 is an apocalyptic number.

It is an amenable number.

13503304155145 is a deficient number, since it is larger than the sum of its proper divisors (5015512971959).

13503304155145 is an equidigital number, since it uses as much as digits as its factorization.

13503304155145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 385808690159.

The product of its (nonzero) digits is 270000, while the sum is 40.

Adding to 13503304155145 its reverse (54155140330531), we get a palindrome (67658444485676).

The spelling of 13503304155145 in words is "thirteen trillion, five hundred three billion, three hundred four million, one hundred fifty-five thousand, one hundred forty-five".

Divisors: 1 5 7 35 385808690147 1929043450735 2700660831029 13503304155145