Search a number
-
+
13503331151 = 43314030957
BaseRepresentation
bin11001001001101110…
…00111101101001111
31021212001220021222222
430210313013231033
5210123323044101
610111531125555
7655424264252
oct144467075517
937761807888
1013503331151
1157aa307612
12274a2a38bb
13137275209b
1492154b099
1554072701b
hex324dc7b4f

13503331151 has 4 divisors (see below), whose sum is σ = 13817362152. Its totient is φ = 13189300152.

The previous prime is 13503331139. The next prime is 13503331159. The reversal of 13503331151 is 15113330531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13503331151 - 214 = 13503314767 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13503331151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13503331159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157015436 + ... + 157015521.

It is an arithmetic number, because the mean of its divisors is an integer number (3454340538).

Almost surely, 213503331151 is an apocalyptic number.

13503331151 is a deficient number, since it is larger than the sum of its proper divisors (314031001).

13503331151 is an equidigital number, since it uses as much as digits as its factorization.

13503331151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 314031000.

The product of its (nonzero) digits is 2025, while the sum is 26.

Adding to 13503331151 its reverse (15113330531), we get a palindrome (28616661682).

The spelling of 13503331151 in words is "thirteen billion, five hundred three million, three hundred thirty-one thousand, one hundred fifty-one".

Divisors: 1 43 314030957 13503331151