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13503410550137 is a prime number
BaseRepresentation
bin1100010010000000000111…
…1111010011010101111001
31202210220122220021010202202
43010200001333103111321
53232214441100101022
644415214155435545
72562406046565644
oct304400177232571
952726586233682
1013503410550137
114336845249a72
121621074a55bb5
1376c49b5840a1
143497d61a0a5b
151863c4908592
hexc4801fd3579

13503410550137 has 2 divisors, whose sum is σ = 13503410550138. Its totient is φ = 13503410550136.

The previous prime is 13503410550107. The next prime is 13503410550193. The reversal of 13503410550137 is 73105501430531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6762761481961 + 6740649068176 = 2600531^2 + 2596276^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13503410550137 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13503410550137.

It is not a weakly prime, because it can be changed into another prime (13503410550107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751705275068 + 6751705275069.

It is an arithmetic number, because the mean of its divisors is an integer number (6751705275069).

Almost surely, 213503410550137 is an apocalyptic number.

It is an amenable number.

13503410550137 is a deficient number, since it is larger than the sum of its proper divisors (1).

13503410550137 is an equidigital number, since it uses as much as digits as its factorization.

13503410550137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 94500, while the sum is 38.

Adding to 13503410550137 its reverse (73105501430531), we get a palindrome (86608911980668).

The spelling of 13503410550137 in words is "thirteen trillion, five hundred three billion, four hundred ten million, five hundred fifty thousand, one hundred thirty-seven".