Base | Representation |
---|---|
bin | 1100010010000000000111… |
… | …1111010011010110110001 |
3 | 1202210220122220021010211211 |
4 | 3010200001333103112301 |
5 | 3232214441100101233 |
6 | 44415214155440121 |
7 | 2562406046566054 |
oct | 304400177232661 |
9 | 52726586233754 |
10 | 13503410550193 |
11 | 433684524a013 |
12 | 1621074a56041 |
13 | 76c49b584115 |
14 | 3497d61a0a9b |
15 | 1863c49085cd |
hex | c4801fd35b1 |
13503410550193 has 2 divisors, whose sum is σ = 13503410550194. Its totient is φ = 13503410550192.
The previous prime is 13503410550137. The next prime is 13503410550221. The reversal of 13503410550193 is 39105501430531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10327662014224 + 3175748535969 = 3213668^2 + 1782063^2 .
It is an emirp because it is prime and its reverse (39105501430531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13503410550193 is a prime.
It is not a weakly prime, because it can be changed into another prime (13503410551193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751705275096 + 6751705275097.
It is an arithmetic number, because the mean of its divisors is an integer number (6751705275097).
Almost surely, 213503410550193 is an apocalyptic number.
It is an amenable number.
13503410550193 is a deficient number, since it is larger than the sum of its proper divisors (1).
13503410550193 is an equidigital number, since it uses as much as digits as its factorization.
13503410550193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121500, while the sum is 40.
The spelling of 13503410550193 in words is "thirteen trillion, five hundred three billion, four hundred ten million, five hundred fifty thousand, one hundred ninety-three".
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