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13503410550193 is a prime number
BaseRepresentation
bin1100010010000000000111…
…1111010011010110110001
31202210220122220021010211211
43010200001333103112301
53232214441100101233
644415214155440121
72562406046566054
oct304400177232661
952726586233754
1013503410550193
11433684524a013
121621074a56041
1376c49b584115
143497d61a0a9b
151863c49085cd
hexc4801fd35b1

13503410550193 has 2 divisors, whose sum is σ = 13503410550194. Its totient is φ = 13503410550192.

The previous prime is 13503410550137. The next prime is 13503410550221. The reversal of 13503410550193 is 39105501430531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10327662014224 + 3175748535969 = 3213668^2 + 1782063^2 .

It is an emirp because it is prime and its reverse (39105501430531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13503410550193 is a prime.

It is not a weakly prime, because it can be changed into another prime (13503410551193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6751705275096 + 6751705275097.

It is an arithmetic number, because the mean of its divisors is an integer number (6751705275097).

Almost surely, 213503410550193 is an apocalyptic number.

It is an amenable number.

13503410550193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13503410550193 is an equidigital number, since it uses as much as digits as its factorization.

13503410550193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 121500, while the sum is 40.

The spelling of 13503410550193 in words is "thirteen trillion, five hundred three billion, four hundred ten million, five hundred fifty thousand, one hundred ninety-three".